here is the p. The product of a number and 6 is decrased by 8. The result is 13 greater than the product of 4 and the same number increased by 3. what is the number???? plazes help and thanks

That's simple. Just write the problem as an equation: (X x 6)-8=13+(4 x (X +3)) Now solve for X: 6X-8=4(X +3)+13 6X-8=(4X+12)+13 6X-8=4X +25 6X=4X+33 2X=33 X=16.5 16.5 is the answer To check the answer, plug 16.5 into the orginal equation: 6(16.5)-8=13+ 4(16.5 + 3 ) 99-8=13+ (66+12) 91=13+78 91=91 Both sides are equal, so the answer 16.5 is correct. [Edited by Keeksy on 02-09-2001 at 08:21 PM]

"here is the p. " someone who posted thought that meant solve for p you solved for x the person thought p but the p might only mean "problem" for short

weeeee! mass confusion? can we solve for L now? L doesn't get much attention! unless you are dealing with aline then maybe you should try g g doesn't get much attention either

Um...This makes me think how an ESL math class would be like. Ugh. We need a clear and concise written question to be able to answer it.

its high school math is anyone going to help me I have the answer to the probelm the answer in one of the answers is wrong. The answer should be 33/2 Thats what it says in the book. No math teacher out there to help with this problem Oh well

Re: its high school math 6x - 8 = 4(x+3) + 13 (expand the brackets and add like terms) 6x - 8 = 4x + 25 (add 8, both sides) 6x = 4x + 33 (subtract 4x, both sides) 2x = 33 (divide by 2 both sides) x = 33/2 Now, don't even THINK of asking me about calculus.